3.12.57 \(\int \frac {(1-2 x) (3+5 x)}{(2+3 x)^6} \, dx\) [1157]

Optimal. Leaf size=34 \[ \frac {7}{135 (2+3 x)^5}-\frac {37}{108 (2+3 x)^4}+\frac {10}{81 (2+3 x)^3} \]

[Out]

7/135/(2+3*x)^5-37/108/(2+3*x)^4+10/81/(2+3*x)^3

________________________________________________________________________________________

Rubi [A]
time = 0.01, antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {78} \begin {gather*} \frac {10}{81 (3 x+2)^3}-\frac {37}{108 (3 x+2)^4}+\frac {7}{135 (3 x+2)^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((1 - 2*x)*(3 + 5*x))/(2 + 3*x)^6,x]

[Out]

7/(135*(2 + 3*x)^5) - 37/(108*(2 + 3*x)^4) + 10/(81*(2 + 3*x)^3)

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rubi steps

\begin {align*} \int \frac {(1-2 x) (3+5 x)}{(2+3 x)^6} \, dx &=\int \left (-\frac {7}{9 (2+3 x)^6}+\frac {37}{9 (2+3 x)^5}-\frac {10}{9 (2+3 x)^4}\right ) \, dx\\ &=\frac {7}{135 (2+3 x)^5}-\frac {37}{108 (2+3 x)^4}+\frac {10}{81 (2+3 x)^3}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]
time = 0.01, size = 21, normalized size = 0.62 \begin {gather*} \frac {-226+735 x+1800 x^2}{1620 (2+3 x)^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((1 - 2*x)*(3 + 5*x))/(2 + 3*x)^6,x]

[Out]

(-226 + 735*x + 1800*x^2)/(1620*(2 + 3*x)^5)

________________________________________________________________________________________

Maple [A]
time = 0.08, size = 29, normalized size = 0.85

method result size
gosper \(\frac {1800 x^{2}+735 x -226}{1620 \left (2+3 x \right )^{5}}\) \(20\)
risch \(\frac {\frac {10}{9} x^{2}+\frac {49}{108} x -\frac {113}{810}}{\left (2+3 x \right )^{5}}\) \(20\)
default \(\frac {7}{135 \left (2+3 x \right )^{5}}-\frac {37}{108 \left (2+3 x \right )^{4}}+\frac {10}{81 \left (2+3 x \right )^{3}}\) \(29\)
norman \(\frac {\frac {3}{2} x +\frac {17}{4} x^{2}+\frac {113}{24} x^{3}+\frac {339}{320} x^{5}+\frac {113}{32} x^{4}}{\left (2+3 x \right )^{5}}\) \(33\)
meijerg \(\frac {3 x \left (\frac {81}{16} x^{4}+\frac {135}{8} x^{3}+\frac {45}{2} x^{2}+15 x +5\right )}{320 \left (1+\frac {3 x}{2}\right )^{5}}-\frac {x^{2} \left (\frac {27}{8} x^{3}+\frac {45}{4} x^{2}+15 x +10\right )}{1280 \left (1+\frac {3 x}{2}\right )^{5}}-\frac {x^{3} \left (\frac {9}{4} x^{2}+\frac {15}{2} x +10\right )}{192 \left (1+\frac {3 x}{2}\right )^{5}}\) \(81\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-2*x)*(3+5*x)/(2+3*x)^6,x,method=_RETURNVERBOSE)

[Out]

7/135/(2+3*x)^5-37/108/(2+3*x)^4+10/81/(2+3*x)^3

________________________________________________________________________________________

Maxima [A]
time = 0.35, size = 39, normalized size = 1.15 \begin {gather*} \frac {1800 \, x^{2} + 735 \, x - 226}{1620 \, {\left (243 \, x^{5} + 810 \, x^{4} + 1080 \, x^{3} + 720 \, x^{2} + 240 \, x + 32\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)*(3+5*x)/(2+3*x)^6,x, algorithm="maxima")

[Out]

1/1620*(1800*x^2 + 735*x - 226)/(243*x^5 + 810*x^4 + 1080*x^3 + 720*x^2 + 240*x + 32)

________________________________________________________________________________________

Fricas [A]
time = 0.65, size = 39, normalized size = 1.15 \begin {gather*} \frac {1800 \, x^{2} + 735 \, x - 226}{1620 \, {\left (243 \, x^{5} + 810 \, x^{4} + 1080 \, x^{3} + 720 \, x^{2} + 240 \, x + 32\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)*(3+5*x)/(2+3*x)^6,x, algorithm="fricas")

[Out]

1/1620*(1800*x^2 + 735*x - 226)/(243*x^5 + 810*x^4 + 1080*x^3 + 720*x^2 + 240*x + 32)

________________________________________________________________________________________

Sympy [A]
time = 0.06, size = 36, normalized size = 1.06 \begin {gather*} - \frac {- 1800 x^{2} - 735 x + 226}{393660 x^{5} + 1312200 x^{4} + 1749600 x^{3} + 1166400 x^{2} + 388800 x + 51840} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)*(3+5*x)/(2+3*x)**6,x)

[Out]

-(-1800*x**2 - 735*x + 226)/(393660*x**5 + 1312200*x**4 + 1749600*x**3 + 1166400*x**2 + 388800*x + 51840)

________________________________________________________________________________________

Giac [A]
time = 1.67, size = 19, normalized size = 0.56 \begin {gather*} \frac {1800 \, x^{2} + 735 \, x - 226}{1620 \, {\left (3 \, x + 2\right )}^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)*(3+5*x)/(2+3*x)^6,x, algorithm="giac")

[Out]

1/1620*(1800*x^2 + 735*x - 226)/(3*x + 2)^5

________________________________________________________________________________________

Mupad [B]
time = 1.12, size = 28, normalized size = 0.82 \begin {gather*} \frac {10}{81\,{\left (3\,x+2\right )}^3}-\frac {37}{108\,{\left (3\,x+2\right )}^4}+\frac {7}{135\,{\left (3\,x+2\right )}^5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-((2*x - 1)*(5*x + 3))/(3*x + 2)^6,x)

[Out]

10/(81*(3*x + 2)^3) - 37/(108*(3*x + 2)^4) + 7/(135*(3*x + 2)^5)

________________________________________________________________________________________